Asked by Anonymous

For the emission spectrum of Be3+, calculate the lowest wavenumber νˉ (in inverse meters) of light produced by electron transitions between n=2, n=3, and n=4.

Answers

Answered by DrBob222
w = wavelength
1/w = RZ^2(1/n1^2 - 1/n2^2)
R = 1.09737E7
Z = 4
n1^2= 3^2= 9
n2^2 = 4^2 = 16
Answered by amar chauhan
8.56*10^6
amar chauhan
Answered by Chavan
What are the concepts used in these?
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