Question

15. What is the solution of the linear-quadratic system of equations?
{y = x^2 + 5x - 3}
{y - x = 2}

Answer 1

Try substituting those values, and you will see they do not fit either equation.

looking at the 2nd equation, y = x+2, so
x+2 = x^2+5x-3
x^2 + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5 or 1
so, y = -3 or 3
the solutions are thus (-5,-3)(1,3)

Answer 2

first things first...calm down. yes, its extremely hard. but we go simple approach. y-x=2 implies y=x+2.we substitute that in the first equation to get x+2 = x^2+5x-3 =x^2+4x-5=0.

We factor to get (x-1)(x+5)=0. Thus, x=1, or -5. PLugging in, we get y=-3,3. Thus, (1,3)(-5,-3) are the solutions

Answer 3

makes no damn sense

Answer 4

what about the first equation?

Answer 5

Find the solutions of the system of equations braceleftze y = x2 + 3 y = x + 15 .

Answer 6

you guys are life savers thank you

Answer 7

does anyone else try to understand this but just can't so you end up cheating?

Answer 8

Yeah but it because algebra get confusing real quick for me.

Answer 9

@ight, no I cheat reguardless. I would have no idea where to start. lmao

Answer 10

ong tho i try to understand math sometimes but it's just so poorly described in class i feel weird trying to ask for extra help when everyone else already understands ._.

Answer 11

lmfao learning algebra 2 is like learning Japanese for me 😂 it makes no sense to me😂😂😂

Answer 12

yall r life savers

Answer 13

How do you know at the end of this equation that y=-3 and 3?