delta T = i*Kf*m
You want to know which solution produces the higher delta T. m is the same, Kf is the same, the only difference is i. i is the van't Hoff factor which is the number of particles.
A does not ionize (at least I assume it doesn't). B ionizes into two particles, C into 3 particles and D into four particles. So stick 1, 2, 3, 4 into the equation. Which gives the higher number for delta T?
Which of the following solutions will have a higher boiling point?
A. 1m C6H12O6
B. 1m NaCl
C. 1m MgCl2
D. 1m AlCl3
And pls explain why it is. Thank you so much!!
4 answers
D.AlCl3 bcos colligative properties are directly proportional to the no. of solute particles. AlCl3 has 4 particles on dissociating.
wats Kf and kb
AlCl3 because it has the most particles upon dissociating.
1 answer