Question
What is the orbital speed of a satellite of mass 490 kg in geostationary orbit?
Answers
bobpursley
the distance in one orbit: 2PI(re+h)
period=24 hrs (convert to seconds).
v=2PI(re+h)/period
gravity acceleration= centripetalacc
9.8 re^2/(re+h)^2 = v^2 (above)/(re+h)
solve for h re is radius earth.
then solve for V
period=24 hrs (convert to seconds).
v=2PI(re+h)/period
gravity acceleration= centripetalacc
9.8 re^2/(re+h)^2 = v^2 (above)/(re+h)
solve for h re is radius earth.
then solve for V