Question

What would be the orbital speed and period of a satellite in orbit 0.88 multiplied by 108 m above the Earth?

Orbital Speed___m/s

Period___s

Thanks!

Answer 1

start with Newtons law of gravity

F=GMem/(re+.88E8)^2

that has to equal centripetal force

GMe m /(re+.88E8)^2= m v^2/(re+.88E8)
solve for v

period? well 2PI(re+.88E8)/period= v
solve for period.