Asked by Paula
Two ships leave San Francisco at the same time. One travles 40 degrees W of N at the speed of 20 knots. The other travels 10 degrees W of south at a speed of 15 knots. How far apart are they after 11 hours?
Answers
Answered by
Reiny
The first one will have travelled 220 nautical miles, the second one 165 n miles.
the angle between their paths is 130º
so dist^2 = 220^2 + 165^2 - 2(220)(165)cos130
= ..
= ..
I am sure you can do the arithmetic.
the angle between their paths is 130º
so dist^2 = 220^2 + 165^2 - 2(220)(165)cos130
= ..
= ..
I am sure you can do the arithmetic.
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