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calculate the delta H for
3 Fe(s) + 4 CO2(g) �¨ 4 CO(g) + Fe3O4(s)
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The arrow is made as --> or ==> or >>>
dHrxn = (n*dHf products) - (n*dHf reactants)
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Given:
*Fe2O3(s)+3CO(s)-->2Fe(s)+3CO2(g)(delta h is -23kJ) *3Fe2O3(s)+CO(g)-->2Fe3O4(s)+CO2(g)(delta h is -39kJ)
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Does my work here look right?
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