Asked by Kim
Consider the reaction
2H2O(g) --> 2H2(g) + O2(g)
deltaH = +483.6 kJ/mol
at a certain temperature. If the increase in volume is 32.7 L against an external pressure of 1.00 atm, calculate deltaU for the reaction. (1 L * atm = 101.3 J)
2H2O(g) --> 2H2(g) + O2(g)
deltaH = +483.6 kJ/mol
at a certain temperature. If the increase in volume is 32.7 L against an external pressure of 1.00 atm, calculate deltaU for the reaction. (1 L * atm = 101.3 J)
Answers
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