Asked by Kevin
How do u find the angles of a triangle whose sides are in the ratio 2:4:5?
Answers
Answered by
Steve
one way is to use the law of cosines.
a^2 = b^2+c^2 - 2bc cosA
Without loss of generality, we may take a to be the smallest side, of length 2. Then,
2^2 = 4^2 + 5^2 - 2*4*5 cosA
A = 22.33
similarly,
B = 49.45
C = 108.22
a^2 = b^2+c^2 - 2bc cosA
Without loss of generality, we may take a to be the smallest side, of length 2. Then,
2^2 = 4^2 + 5^2 - 2*4*5 cosA
A = 22.33
similarly,
B = 49.45
C = 108.22
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.