Asked by beracah
HELP me find the angles from the following equation (4cotx+3)(cotx-1) = 0
Answers
Answered by
bobpursley
well,then
cotX=-3/4 or cotx-1
which means
X=arcTan(-4/3) is in quad II or IV
= 90+53.13, or 360-53.13 deg
if cotx=1, then tanx=1, so x is in quad I or III
x=45deg,or 180+45deg
cotX=-3/4 or cotx-1
which means
X=arcTan(-4/3) is in quad II or IV
= 90+53.13, or 360-53.13 deg
if cotx=1, then tanx=1, so x is in quad I or III
x=45deg,or 180+45deg