Asked by Amanda
If 92.75 mg of Na2CO3 is dissolved in 0.5mL of water, what would be the normality of the solution after the addition of 0.67 mL of water.
Answers
Answered by
DrBob222
0.09275g/molar mass = mols Na2CO3
(We assume, I suppose, that the volumes of water are additive--they aren't always additive) so add 0.67 mL + 0.50 mL and convert to L.
M = mols/L.
For N = M x 2.
(We assume, I suppose, that the volumes of water are additive--they aren't always additive) so add 0.67 mL + 0.50 mL and convert to L.
M = mols/L.
For N = M x 2.
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