Question

If 33.6 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? AND if 2.1 moles of CaCl2 are dissolved in enough water to make a .92 liter solution what is the resulting molarity? Please help and explain or anything?!
% w/w = (grams solute/total grams) x 100 =
[33.6 g KCl/(33.6+192)]*100 = ?

M = moles/L soln = 2.1 mols/0.92L = ?
14.9%

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