Asked by Dr. David

If 33.6 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? AND if 2.1 moles of CaCl2 are dissolved in enough water to make a .92 liter solution what is the resulting molarity? Please help and explain or anything?!
Answered by DrBob222
% w/w = (grams solute/total grams) x 100 =
[33.6 g KCl/(33.6+192)]*100 = ?

M = moles/L soln = 2.1 mols/0.92L = ?
Answered by Anonymous
14.9%
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