10.X^11/x^4
A. X^7
B. X^15
C. X^44
D.x 11/4
8.f2 ∙ f4
A. (2f)^8
B. (2f)^6
C. F^8
D. F^6
9 answers
just normal indices rule
a^b/a^a=a^(b-a)
with that hint
play around with your question
a^b/a^a=a^(b-a)
with that hint
play around with your question
I'm not sure
125 · 5=?
can,t you do normal multiplication?
you should be able to do that
you should be able to do that
Yay I can
or you mean
since
a^b.a^a=a^b+a
then
5^3.5^1=?
since
a^b.a^a=a^b+a
then
5^3.5^1=?
first of all get your notation straight. Use ^ for exponents. Second follow the rule that Collins gave you (sort of):
a^b/a^c=a^(b-c)
and
a^b a^c = a^(b+c)
a^b/a^c=a^(b-c)
and
a^b a^c = a^(b+c)
f^8..easy