A stone is thrown at an angle of 30 degrees above the horizontal from the top of a cliff with an initial speed of 12 m/s. If it hits the ground 4.6 seconds later, what is the height of the cliff?

Answer 1

h=hi=Vi*t-4.9t^2 where vi=12sin30, hf=0

hi=4.9t^2-6t and t=4.6 solve for hi

Answer 2

59.8 metres