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A man pulls a crate of mass 63.0 kg across a level floor. He pulls with a force of 174.0 N at an angle of 22.0° above the horiz...Asked by Courtney
A man pulls a crate of mass 53.0 kg across a level floor. He pulls with a force of 180.0 N at an angle of 28.0° above the horizontal. When the crate is moving, the frictional force between the floor and the crate has a magnitude of 124.0 N.
If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.70 m?
If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.70 m?
Answers
Answered by
Damon
180 cos 28 = 159 N horizontal pull
net horizontal force = 159 - 124 = 35 N
Now if the question is what is the acceleration then it is
a = F/m = 35/53 = 0.66 m/s^2
net horizontal force = 159 - 124 = 35 N
Now if the question is what is the acceleration then it is
a = F/m = 35/53 = 0.66 m/s^2
Answered by
courtney
oh sorry its
If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.70 m?
If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.70 m?
Answered by
Damon
d = (1/2) a t^2
Answered by
Damon
and v = a t
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