Fx = 186 cos 22
Fz = 186 sin 22
186 cos 22 - 120 = 61 a
a = (1/61) 52.5
= .86 m/s^2
v = a t = .86 t
average v = .43 t
2.5 = .43 t * t
t = 2.41 seconds
so v = .86 (2.41) = 2.07 m/s
A man pulls a crate of mass 61.0 kg across a level floor. He pulls with a force of 186.0 N at an angle of 22.0° above the horizontal. When the crate is moving, the frictional force between the floor and the crate has a magnitude of 120.0 N. If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.50 m?
1 answer
1 answer