I think you will find that if you mean
1/(2x^2-x+5)=0
there is no solution. The graph has a horizontal asymptote at y=0, meaning it never is really 0.
If that's not what you intended, then please clarify.
what is the solution
1/2x^2-x+5=0
could someone please explain
5 answers
the possible answers are;
1+-i sqrt 11
-1+-i sqrt 9
1 +- i sqrt 9
-1 +- i sqrt 11
1+-i sqrt 11
-1+-i sqrt 9
1 +- i sqrt 9
-1 +- i sqrt 11
i figured it out to be 1+isqrt9
1. D 2isqrt7
2. B over 4 up 2
3. B 11-2i
4. C 20-4i
5. A 31+i/26
6. B 1+isqrt9
You're welcome
2. B over 4 up 2
3. B 11-2i
4. C 20-4i
5. A 31+i/26
6. B 1+isqrt9
You're welcome
just took the quiz
1. D ( 2i sqrt7 )
2. Graph B (imaginary : 2, Real : 4)
3. B ( 11-2i )
4. C ( 20-4i )
5. A ( 31+i / 26)
6. C ( 1 +/- i sqrt 9 )
1. D ( 2i sqrt7 )
2. Graph B (imaginary : 2, Real : 4)
3. B ( 11-2i )
4. C ( 20-4i )
5. A ( 31+i / 26)
6. C ( 1 +/- i sqrt 9 )