Question
A 4.47 g sample of a molecular compound is dissolved in 96 g of tetrachloromethane. The normal boiling point of the solution is 61.51 degrees celcius, the normal boiling point for CCl4 is 61.2 degrees celsius. The boiling point constant for CCl4 is 4.95K*kg/mol. What is the molar mass of the compound? Answer in units of g/mol
I know you have to use the formula:
delta Tb = iKbm but I have no clue how start or find the molality.
PLEASE HELP
I know you have to use the formula:
delta Tb = iKbm but I have no clue how start or find the molality.
PLEASE HELP
Answers
Note the correct spelling of celsius.
Why don't you start with delta T = i*Kb*m
You can calculate delta T, i = 1 since it is a molecular compound, you know Kb and solve for m.
Then m = mols/kg solvent. You know m and kg solvent, solve for mols.
Then mols = grams/molar mass. You know mols and grams, solve for molar mass.
Why don't you start with delta T = i*Kb*m
You can calculate delta T, i = 1 since it is a molecular compound, you know Kb and solve for m.
Then m = mols/kg solvent. You know m and kg solvent, solve for mols.
Then mols = grams/molar mass. You know mols and grams, solve for molar mass.