Asked by Jake
A rectangular cardboard poser is to have 150 sq ft in for printed matter. It is to have a 3inch margin at the top and bottom and a 2inch margin at the right and left. Find the dimensions of the poser so that the amount of cardboard used is minimized.
Answers
Answered by
Steve
if the cardboard has height x and width y,
a = xy
printed area is (x-6)(y-4) = 150
so, we want to minimize xy.
a = xy = x(150/(x-6) + 4)
da/dx = 4(x^2-12x-189)/(x-6)^2
since the denominator is never zero, da/dx=0 when
x^2 - 12x - 189 = 0
(x+9)(x-21) = 0
so, x = 21
y = 14
area of poster is 294
area of printing is 15x10 = 150
a = xy
printed area is (x-6)(y-4) = 150
so, we want to minimize xy.
a = xy = x(150/(x-6) + 4)
da/dx = 4(x^2-12x-189)/(x-6)^2
since the denominator is never zero, da/dx=0 when
x^2 - 12x - 189 = 0
(x+9)(x-21) = 0
so, x = 21
y = 14
area of poster is 294
area of printing is 15x10 = 150
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.