Question
a helicopter, travelling horizontally at a constant velocity, is 82m above ground. The pilot prepares to release a package intended to land on the ground 96m horizontally ahead. no air resistance. He lets the package drop. what is the velocity of the helicopter?
Answers
MathMate
The package was released 82 m above ground. With no air resistance, and acceleration due to gravity = 9.81, time it takes is
82 = (1/2)gt²
t=sqrt(2*82/9.81)
= 4.089 s.
During this time, the helicopter has travelled 96 m horizontally, therefore
Velocity of helicopter = 96/4.089=23.48m/s
82 = (1/2)gt²
t=sqrt(2*82/9.81)
= 4.089 s.
During this time, the helicopter has travelled 96 m horizontally, therefore
Velocity of helicopter = 96/4.089=23.48m/s