Asked by Ashley
You are driving off of a horizontal cliff, again!!! The cliff is measured to be 35.56 m above a rocky ravine floor, but you land 10.36 m away from the sheer cliff face.
How fast were you going when you drove off of the cliff?
How fast were you going when you drove off of the cliff?
Answers
Answered by
MathMate
Time to free-fall 35.56m
= sqrt(2*S/g)
= sqrt(2*35.56/9.81)
= 2.6925 s
Horizontal velocity does not change during free fall, so
v= Dist/time
= 10.36 m/2.6925s
= 3.81 m/s
= sqrt(2*S/g)
= sqrt(2*35.56/9.81)
= 2.6925 s
Horizontal velocity does not change during free fall, so
v= Dist/time
= 10.36 m/2.6925s
= 3.81 m/s
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