If a projectile is fired with velocity v0 at an angle θ, then its range, the horizontal distance it travels (in feet), is modeled by the function

Question

R(θ) =
v02 sin 2θ
32
.
If
v0 = 2600 ft/s,
what angle (in degrees) should be chosen for the projectile to hit a target on the ground 5000 ft away? (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
Thanks

Answer 1

ind the key numbers of the expression. (Enter your answers as a comma-separated list.)
3x2 − x − 10

Answer 2

21.1