Asked by Ama
If a projectile is fired with velocity v0 at an angle θ, then its range, the horizontal distance it travels (in feet), is modeled by the function
R(θ) =
v02 sin 2θ
32
.
If
v0 = 2600 ft/s,
what angle (in degrees) should be chosen for the projectile to hit a target on the ground 5000 ft away? (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
Thanks
R(θ) =
v02 sin 2θ
32
.
If
v0 = 2600 ft/s,
what angle (in degrees) should be chosen for the projectile to hit a target on the ground 5000 ft away? (Enter your answers as a comma-separated list. Round your answers to three decimal places.)
Thanks
Answers
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