Asked by Allison

Karla is riding vertically in a hot air balloon, directly over a point P on the ground. Karla spots a parked car on the ground at an angle of depression of 30o. The balloon rises 50 meters. Now the angle of depression to the car is 35°. How far is the car from point P?
Answered by Henry
We form 2 similar rt. triangles:

Triangle #1.
X = Hor. side = dist. from P to the car.
Yi = Ver. side.
A = 30o.

Triangle #2.
X = Hor. side = Dist. from P to the car.
Y2 = Y1+50 = Ver. side.
A = 35o.

Use aw of Sines.
sin30/Y1 = sin35/(Y1+50).
Cross multiply:
(Y1+50)sin30 = Y1*sin35
Y1/2+25 = 0.574Y1
Multiply both sides by 2:
Y1+50 = 1.148Y1
1.148Y1-Y1 = 50
0.148Y1 = 50
Y1 = 337.8 m.

tan30 = Y1/X = 337.8/X
X = 337.8/tan30 = 585 m.

Answered by Hhh
714 feet away
Answered by kale
I gave up.
Answered by imheretohelp
234.97
Answered by sean john
this is just common sense. How can the angle of depression be higher when karla rises. If she is rising, it is physically impossible for the angle of depression to go higher. This question isnt worded right.
Answered by Idk
I read the first word and gave up 🤣
Answered by g🦋
The hot air balloon has an angle of depression of 36° to the point of the ground. The distance between the hot air balloon and the ground is 75 ft.
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