so, if Karla's age is x,
Ama is x+3
Daniel is x+3+2 = x+5
So, adding them all up,
x + x+3 + x+5 = 32
3x+8 = 32
3x = 24
x = 8
Their ages are 8,11,13
Ama, Karla and Daniel are siblings. Ama is 3 years older than Karla and Daniel is 2 years older than Ama.The sum of their ages is 32. How old is each child.
Please help me I don't know what to do, it's my High School Summer Holiday Homework!!! But I'm still in Sixth Grade!!!
2 answers
A = Ama's ages
K = Karla's ages
D = Daniel's ages
Ama is 3 years older than Karla
this mean :
A = K + 3
Daniel is 2 years older than Ama
this mean :
D = A + 2
The sum of their ages is 32
this mean :
A + K + D = 32
Now you have 3 equatios :
A = K + 3
D = A + 2
A + K + D = 32
A = K + 3
D = A + 2
D = ( K + 3 ) + 2
D = K + 3 + 2 = K + 5
A + K + D = 32
( K + 3 ) + K + ( K + 5 ) = 32
K + 3 + K + K + 5 = 32
3 K + 8 = 32 Subtract 8 to both sides
3 K + 8 - 8 = 32 - 8
3 K = 24 Divide both sides by 3
3 K / 3 = 24 / 3
K = 8
Karla is 8 years old
D = K + 5
D = 8 + 5 = 13
Daniel is 13 years old
A = K + 3
A = 8 + 3 = 11
Ama is 11 years old
K = Karla's ages
D = Daniel's ages
Ama is 3 years older than Karla
this mean :
A = K + 3
Daniel is 2 years older than Ama
this mean :
D = A + 2
The sum of their ages is 32
this mean :
A + K + D = 32
Now you have 3 equatios :
A = K + 3
D = A + 2
A + K + D = 32
A = K + 3
D = A + 2
D = ( K + 3 ) + 2
D = K + 3 + 2 = K + 5
A + K + D = 32
( K + 3 ) + K + ( K + 5 ) = 32
K + 3 + K + K + 5 = 32
3 K + 8 = 32 Subtract 8 to both sides
3 K + 8 - 8 = 32 - 8
3 K = 24 Divide both sides by 3
3 K / 3 = 24 / 3
K = 8
Karla is 8 years old
D = K + 5
D = 8 + 5 = 13
Daniel is 13 years old
A = K + 3
A = 8 + 3 = 11
Ama is 11 years old