Asked by kathy
standing on the ground, you throw a 0.55 kg lunch bag at a friend, you manage to throw the bag straight up (vertically) using 50 J of energy to throw it there is also a crosswind of 0.5 m/s. How high will the bag travel before all of its kinetic energy is converted into gravitational potential energy?
Answers
Answered by
Elena
KE=PE
KE=mgh
h=KE/mg =50/0.55•9.8 =9.28 m
KE=mgh
h=KE/mg =50/0.55•9.8 =9.28 m
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