Question
A boy 12.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the instant the ball is thrown. If the boy throws the ball horizontally at 8.50 m/s, (a) how fast must the dog run to catch the ball just as it reaches the ground, and (b) how far from the tree will the dog catch the ball?
Answers
use the freefall equation to find the flight time
... h = 1/2 g t^2 + vo t + ho
... 0 = -4.90 t^2 + 0 + 12.0
(b) flight time * 8.50 m/s
(a) the dog must run as fast as the horizontal component of the ball's velocity
... 8.50 m/s
... h = 1/2 g t^2 + vo t + ho
... 0 = -4.90 t^2 + 0 + 12.0
(b) flight time * 8.50 m/s
(a) the dog must run as fast as the horizontal component of the ball's velocity
... 8.50 m/s
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