Question

One buffer solution used to calibrate a pH electrode was made by dissolving 2.24g of potassium propanoate, C2H5COOK, in 250cm3 of 0.20 mooll-1 propanoic acid.
I assume you want the pH of the solution.
pH = pKa + log(base)/(acid)
Substitute and solve or pH.

Related Questions

What is th pH of a buffer solution made by dissolving 0.10 mol of formic acid, HCOOH, and 0.10 mol o... Calculate the pH of the following buffer solutions: a) a solution made by dissolving 2.733g KH2PO4... A pH = 7.6 buffer is needed in the lab. This buffer is made by first dissolving 17.42 g K2HPO4 in 6...