Asked by Nevaeh
A 500 mL buffer solution is 0.1 M benzoic acid and 0.10 M in sodium benzoate and has an initial pH of 4.19. What is the pH of the buffer upon addition of 0.010 mol of NaOH?
Answers
Answered by
DrBob222
Let's call benzoic acid HB and sodium benzoate is NaB. NaB is the base; HB is the acid.
.......HB + NaOH ==> NaB + H2O
I......0.1....0.......0.1......
add.........0.01..............
C....-0.01..-0.01......+0.01
E.....0.09.....0.......0.11
Substitute the E line into the Henderson-Hasselbalch equation and solve for pH.
.......HB + NaOH ==> NaB + H2O
I......0.1....0.......0.1......
add.........0.01..............
C....-0.01..-0.01......+0.01
E.....0.09.....0.......0.11
Substitute the E line into the Henderson-Hasselbalch equation and solve for pH.