Asked by Physics Failure
A proton and an electron enter perpendicular to the direction of the magnetic field. The speed of the proton is twice the speed of the electron. What is the ratio of the force experienced by the proton to the electron?
1:2
1:3
2:1
3:1
I would think A, but I want to make sure...
1:2
1:3
2:1
3:1
I would think A, but I want to make sure...
Answers
Answered by
Elena
F=qvBsinα
sinα=1 => F=qvB
F(p)=e2vB
F(e) =evB
F(p)/F(e) =2
...2:1
sinα=1 => F=qvB
F(p)=e2vB
F(e) =evB
F(p)/F(e) =2
...2:1
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