Asked by kkpdiluvu

An electron and a proton have charges of an equal magnitude but opposite sign of 1.6 10-19 C. If the electron and proton in a hydrogen atom are separated by a distance of 5.4 10-11 m, what are the magnitude and direction of the electrostatic force exerted on the electron by the proton?

I don't really understand Coulomb's Law... HELP!!
Answered by bobpursley
Show me your work.
Answered by kkpdiluvu
F=k*q1*q2/r^2
k= 8.99^9
q1= 1.6^-19
q2= -1.6^-19
r^2= 5.4^-11
am i even close?
Answered by kkpdiluvu
the ^ should be e sorry...
Answered by bobpursley
That is correct, however, you have to square r.
Answered by kkpdiluvu
So is -7.89e-8 my answer? Sorry I only have one more time to put it in my homework and I want to make sure I got it right this time!
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