Question
I titrated 0.25 grams of soda ash with 43.7 mL of HCl (0.115M) and 25 mL of H2O. I am getting over 100% sodium carbonate in my answer here are my steps that I took to get the answer can somebody help me see what I did wrong?
mols HCl=(0.115M)x (0.0437L)=0.005 mol HCl
1/2 x (0.005)= 0.0025mol Na2CO3
0.0025mol x 105.99g= 0.42g Na2CO3
0.42g/0.25g x 100%= 168%
mols HCl=(0.115M)x (0.0437L)=0.005 mol HCl
1/2 x (0.005)= 0.0025mol Na2CO3
0.0025mol x 105.99g= 0.42g Na2CO3
0.42g/0.25g x 100%= 168%