Asked by reba

the perimeter of a dog park is 156 ft. If the length of the park is 2 ft. less than 3 times the width, what are the dimensions of the dog park?
Answered by Reiny
width ---- w
length ---- 3w - 2

2w + 2(3w-2) = 156
2w + 6w - 4 = 156
8w = 160
w = 20

park is 20 by 58
Answered by Jane
The dimensions of the dog part are 20ft by 56 ft.

Set up the problem

w + w + ( 3w - 2 ) + ( 3w - 2 ) = 156
Answered by Ms. Sue
P = 2L + 2W

156 = 2(3W - 2) + 2W

156 = 6W - 4 + 2W

160 = 8W

20 = W

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L = 58
Answered by Jane
sorry I post 56 instead of 58, the dimensions are 20ft by 58ft
Answered by Hello
How did you get the length to be 58. Where did that number come from?
Answered by Hello
ohhhhh nvrm i got
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