Beginning energy: 1/2 m 15^2
lost energy while slowing: mg*(cos20)*(mu)distance
gained energy while slowing: mg (d/sin20)
final energy=0
finalenergy=betinning enrgy+gained energy-lost energy
0=1/2 m 15^2+mg*d/sin20-.8 mg*(cos20)*d
solve for diistance d
a skier moving at 15 m/s down a 20 degree slope encounters a region of wet snow of coefficient of friction is 0.8. how far down the slope does she go before stopping
2 answers
The mass is not given in the problem, does that mean it cancels out?