Asked by Anon
A 62 kg water skier, moving at 14 m/s , lets go of the towline.
Momentum= 868 kgm/s
Impulse= -868 Ns
c.If the water exerts an average force of -275 N on the skier, how long must the force act? 3.16 s
d. How far does she travel during this time?
I'm guessing "this time" mentioned in the question is 3.16 s
Momentum= 868 kgm/s
Impulse= -868 Ns
c.If the water exerts an average force of -275 N on the skier, how long must the force act? 3.16 s
d. How far does she travel during this time?
I'm guessing "this time" mentioned in the question is 3.16 s
Answers
Answered by
Damon
Get average acceleration during the 3.16 seconds from
a = 14 m/s / 3.16 s
then d = 14 (3.16) - (1/2)(a) (3.16)^2
or more easily from average speed = 7 m/s
so
7 * 3.16
a = 14 m/s / 3.16 s
then d = 14 (3.16) - (1/2)(a) (3.16)^2
or more easily from average speed = 7 m/s
so
7 * 3.16
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