Asked by good _one_here
A shot putter launches a 6.910 kg shot by pushing it along a straight line of length 1.650 m and at an angle of 33.80° from the horizontal, accelerating the shot to the launch speed from its initial speed of 2.500 m/s (which is due to the athlete's preliminary motion). The shot leaves the hand at a height of 2.110 m and at an angle of 33.80°, and it lands at a horizontal distance of 15.10 m. What is the magnitude of the athlete's average force on the shot during the acceleration phase? (Hint: Treat the motion during the acceleration phase as though it were along a ramp at the given angle.)
Answers
Answered by
good _one_here
Someone please Help !!!!!!!!!!!
Answered by
Elena
Vx•t = 15.1
V•cos(33.8) •t = 15.1
t=15.1/(V•cos33.8) (1)
Vy•t+ a•t²/2 = 2.11
V•sin(33.8)•t - 0.5•(9.8)•t²= -2.11 (2)
Plugging (1) into(2)
V•sin(33.2)( 15.1/(V•cos33.8) - 4.9•{15.1/(V•cos33.8) }2 = -2.11,
tan(33.8)•(15.1)- 4.9•(15.1/(V•cos33.8))2 = -2.11.
Solve for final speed V
V=11.5 m/s
Now that you have the final velocity you can now solve for the acceleration.
V ²= V₀ ²+ 2•a•x
a= (V ²- V₀ ² )/2•x =(11.5²-2.5²)/2•1.65 =38.18 m/s²
F=m•a=6.91•38.18=263.8 N
V•cos(33.8) •t = 15.1
t=15.1/(V•cos33.8) (1)
Vy•t+ a•t²/2 = 2.11
V•sin(33.8)•t - 0.5•(9.8)•t²= -2.11 (2)
Plugging (1) into(2)
V•sin(33.2)( 15.1/(V•cos33.8) - 4.9•{15.1/(V•cos33.8) }2 = -2.11,
tan(33.8)•(15.1)- 4.9•(15.1/(V•cos33.8))2 = -2.11.
Solve for final speed V
V=11.5 m/s
Now that you have the final velocity you can now solve for the acceleration.
V ²= V₀ ²+ 2•a•x
a= (V ²- V₀ ² )/2•x =(11.5²-2.5²)/2•1.65 =38.18 m/s²
F=m•a=6.91•38.18=263.8 N
Answered by
Anonymous
I don't think that's the right soluyion i have tried thia and i got it wrong on my assignment
Answered by
Elena
Misprint Vy•t - a•t²/2 = 2.11.
The solution is correct. Check my calculations
The solution is correct. Check my calculations
Answered by
Greg
You need to account for the force of gravity which also has to be overcome and which you ignored.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.