Asked by Mary

Determine the tension in a 40 cm long pendulum when a bob of mass 200g moving at 0.7 m.s is 15 degrees from the vertical?
Answered by Mary
correction the velocity is 0.7 m/s
Answered by drwls
The tension in the string minus the weight component in the string direction equals the centripetal force.

T - M*g cos15 = M V^2/R

M = 0.200 Kg
R = 0.40 m
g = 9.8 m/s^2
V = 0.7 m/s

Solve for T.
Answered by Mary
would the radius be half of the 0.40m?
Answered by bobpursley
no radius is .4m.
Answered by Mary
Thank you!
Answered by pat
Two blocks move along a linear path on a nearly frictionless air track. One block, of mass 0.120 kg, initially moves to the right at a speed of 4.90 m/s, while the second block, of mass 0.240 kg, is initially to the left of the first block and moving to the right at 7.40 m/s. Find the final velocities of the blocks, assuming the collision is elastic.
So what is the velocity of the 0.120 kg block and the0.240 kg block?
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