Asked by kajal
Evaluate the following indefinite integral
integral of the funtion (x^3)/(x^2-49)dx
integral of the funtion (x^3)/(x^2-49)dx
Answers
Answered by
Reiny
by long division:
x^3/(x^2 - 49) = x + 49x/(x^2 - 49)
whose integral is
(1/2)x^2 + (1/98) ln (x^2-49) + c
x^3/(x^2 - 49) = x + 49x/(x^2 - 49)
whose integral is
(1/2)x^2 + (1/98) ln (x^2-49) + c
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