Asked by Andresito
                evaluate the following indefinite integrals by substitution & check the result by differentiation.
∫(sin2x)^2 cos2xdx
            
        ∫(sin2x)^2 cos2xdx
Answers
                    Answered by
            Bosnian
            
    Go on: wolframalpha dot com 
When page be open in rectangle type:
integrate (sin(2x))^2cos(2x)dx
and click option =
After few seconds when you see result click option: Show steps
Then in rectangle type:
derivative (1/6)sin(2x)^3
click option =
and Show steps
On wolframalpha dot com you can practice any kind of calculus.
    
When page be open in rectangle type:
integrate (sin(2x))^2cos(2x)dx
and click option =
After few seconds when you see result click option: Show steps
Then in rectangle type:
derivative (1/6)sin(2x)^3
click option =
and Show steps
On wolframalpha dot com you can practice any kind of calculus.
                    Answered by
            Steve
            
    or, just look at the problem. Substitute
u = sin 2x
du = 2cos2x dx
and you have
∫u^2 du/2
If that gives you trouble, you got some catching up to do...
    
u = sin 2x
du = 2cos2x dx
and you have
∫u^2 du/2
If that gives you trouble, you got some catching up to do...
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