Asked by Andresito
evaluate the following indefinite integrals by substitution & check the result by differentiation.
∫(sin2x)^2 cos2xdx
∫(sin2x)^2 cos2xdx
Answers
Answered by
Bosnian
Go on: wolframalpha dot com
When page be open in rectangle type:
integrate (sin(2x))^2cos(2x)dx
and click option =
After few seconds when you see result click option: Show steps
Then in rectangle type:
derivative (1/6)sin(2x)^3
click option =
and Show steps
On wolframalpha dot com you can practice any kind of calculus.
When page be open in rectangle type:
integrate (sin(2x))^2cos(2x)dx
and click option =
After few seconds when you see result click option: Show steps
Then in rectangle type:
derivative (1/6)sin(2x)^3
click option =
and Show steps
On wolframalpha dot com you can practice any kind of calculus.
Answered by
Steve
or, just look at the problem. Substitute
u = sin 2x
du = 2cos2x dx
and you have
∫u^2 du/2
If that gives you trouble, you got some catching up to do...
u = sin 2x
du = 2cos2x dx
and you have
∫u^2 du/2
If that gives you trouble, you got some catching up to do...