Asked by Chris

How many moles of KBr are present in 120mL of a 0.290M solution?

Answers

Answered by DrBob222
mols = M x L = ?
Answered by tracey
moles = grams/mol. wt.

4.141g/119mol.wt. = 0.03479832g
Answered by DrBob222
I'd rather do it in one step.
mol = M x L = 0.290 x 0.120 = 0.0348
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