Question

deriv.
h(t)=(tˆ4-1)ˆ3(tˆ3+1)ˆ4

Answer 1

product rule and chain rule:

h = uv
h' = u'v + uv'

if u=w^n, u' = n w^(n-1) w'

so, whatcha got?

Answer 2

(3t^4-3)^2(4t^6+4t^3)^4+(t^4-1)^3(12t^4+12t)^3
but i'm not sure if this is a simple as it gets.