Asked by ravinder
Find the first and second derivative of the function
y=f(x)=x^3/(1-(x^2))
Use the information about the derivatives to determine any local maxima and minima, regions where the curve iss concave up or down, and any inflection points
y=f(x)=x^3/(1-(x^2))
Use the information about the derivatives to determine any local maxima and minima, regions where the curve iss concave up or down, and any inflection points
Answers
Answered by
Steve
y = x^3/(1-x^2)
y' = -x^2(x-3)/(1-x^2)^2
y'' = -2x(x^2+3)/(1-x^2)^3
since the denominator is always positive or 0, y' and y'' are zero when the numerators are zero, and undefined at x=±1.
Now it should be easy to read off the increasing/decreasing/concavity intervals.
y' = -x^2(x-3)/(1-x^2)^2
y'' = -2x(x^2+3)/(1-x^2)^3
since the denominator is always positive or 0, y' and y'' are zero when the numerators are zero, and undefined at x=±1.
Now it should be easy to read off the increasing/decreasing/concavity intervals.
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