Asked by Kay
The combustion of 132 g of propane, C3H8, with excess oxygen liberates 6.6x10^3 kj of heat. What is the enthalpy change for the reaction below:
C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l)
C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l)
Answers
Answered by
DrBob222
6.6E3 kJ x x 44.097/132 = ? kJ
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