Asked by Kay

The combustion of 132 g of propane, C3H8, with excess oxygen liberates 6.6x10^3 kj of heat. What is the enthalpy change for the reaction below:

C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l)
Answered by DrBob222
6.6E3 kJ x x 44.097/132 = ? kJ