Asked by Tom
ÚABC ~= ÚACB
BD perpendicular AC
The sum fo the three angles in any triangle is 180 degree.
Prove: mÚCBD = 1/2 mÚBAC
BD perpendicular AC
The sum fo the three angles in any triangle is 180 degree.
Prove: mÚCBD = 1/2 mÚBAC
Answers
Answered by
Tom
angle ABC ~= angle ACB
BD perpendicular AC
The sum fo the three angles in any triangle is 180 degree.
Prove: mangle CBD = 1/2 mangle BAC
BD perpendicular AC
The sum fo the three angles in any triangle is 180 degree.
Prove: mangle CBD = 1/2 mangle BAC
Answered by
Reiny
let angle CBD = a
in trianagle ABC:
2x + y = 180
in triangle BCD
a + x = 90 or 2a + 2x = 180
then 2a + 2x = 2x + y , both equal to 180
2a = y
a = (1/2y
or
angle CBD = (1/2) angle BAC
in trianagle ABC:
2x + y = 180
in triangle BCD
a + x = 90 or 2a + 2x = 180
then 2a + 2x = 2x + y , both equal to 180
2a = y
a = (1/2y
or
angle CBD = (1/2) angle BAC
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