Asked by olivia
the equation of a line perpendicular to the line y = x - 3 and containing the point (8, -2).
Answers
Answered by
Reiny
slope of given line = 1
slope of perpendicular line = -1
so new equation :
y = -x + b
plug in the point ...
-2 = -1(8) + b
b = 6
new equation: y = -x + 6
slope of perpendicular line = -1
so new equation :
y = -x + b
plug in the point ...
-2 = -1(8) + b
b = 6
new equation: y = -x + 6
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