Asked by olivia

the equation of a line perpendicular to the line y = x - 3 and containing the point (8, -2).
Answered by Reiny
slope of given line = 1
slope of perpendicular line = -1

so new equation :
y = -x + b
plug in the point ...
-2 = -1(8) + b
b = 6

new equation: y = -x + 6