Asked by senko

Calculate the number of moles of KIO3 consumed by reaction (2.1). Remember, it is the limiting reagent. Using this information, calculate the number of moles of I- that must have been consumed by reaction.
Unbalanced equation: IO -(aq) + I-(aq) + H+(aq) ÿ I (aq) + H O(l)

Concentration of KIO3 is 0.1201 mol/l
Volume of KIO3 is 5.00ml or 0.005 L

I got the amount of mols for KIO3 but have no idea how to get it for I-
Answered by mike
Hey this is the same uoit lab I just completed and submitted, if you can tell me your value again for KLO3 (amount of mols) i'll be able to solve it for you
Answered by mike
repost, did you do 0.1201 * 0.005=6*10^-4, if so then you'd subtract this number from the one calculated in part 2 and there's your answer
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