Asked by Kyle
In a tracer method the potassium isotope 42K is used for labelling. The half life of 42K is 12.5 hours. If No is original number of atoms, how many hours will it take until only (1/1024) No Atoms remain?
The answer is 125 hours but I do not know how to get this. Please help!
The answer is 125 hours but I do not know how to get this. Please help!
Answers
Answered by
bobpursley
Goodness.
change the prior problem to
1/1024=(1/2)^(t/12.5)
change the prior problem to
1/1024=(1/2)^(t/12.5)
Answered by
Damon
2 to the what = 1024 ?
(If you do not know instantly do this
2^x = 1024 )
x log 2 = log 1024
x = 10
so
(1/2)^10 = 1/1024
t/12.5 = 10
t = 125
(If you do not know instantly do this
2^x = 1024 )
x log 2 = log 1024
x = 10
so
(1/2)^10 = 1/1024
t/12.5 = 10
t = 125
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