Asked by Mira
What is the pH for the potassium propionate solution at the equivalence point?
Answers
Answered by
DrBob222
The pH is determined by the hydrolysis of the propionate ion, which I will call Pr^-
Pr^- + HOH ==> HPr + OH^-
Set up an ICE chart and substitute into the following Kb expression.
Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-)
Kw you know
Ka you know
(HPr) = (OH^-) = x
(Pr^-) = you don't have that in the problem but it is the concn of the salt at that point.
Solve for x, I would then convert to pOH, then subtract from 14 to obtain pH.
Pr^- + HOH ==> HPr + OH^-
Set up an ICE chart and substitute into the following Kb expression.
Kb = (Kw/Ka) = (HPr)(OH^-)/(Pr^-)
Kw you know
Ka you know
(HPr) = (OH^-) = x
(Pr^-) = you don't have that in the problem but it is the concn of the salt at that point.
Solve for x, I would then convert to pOH, then subtract from 14 to obtain pH.
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