Integrate Sin(rootx) wrt x

Answer 1

∫sin√x dx

let
u = √x
du = 1/(2√x) dx
dx = 2√x du = 2u du

∫sin√x dx = ∫sinu (2u du)
= 2∫u sinu du

now use integration by parts to get

2sinu - 2u cosu

and convert back to x's