Asked by Becca
The maximum speed of a child on a swing is 4.90 m/s. The child's height above the ground is 0.525 m at the lowest point in his motion. How high above the ground is he at his highest point?
Answers
Answered by
Elena
h₀=0.525 m, v = 4.9 m/s, H=?
mv²/2= mgh
h= v²/2g
H=h+h₀= v₀²/2g + h₀
mv²/2= mgh
h= v²/2g
H=h+h₀= v₀²/2g + h₀
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