Asked by Nora
Assume a perfectly elastic collision between a 916g bat and a 145g baseball. Initially, the ball was moving at 32 m/s toward the ball and afterward it's heading away at 40 m/s.
Find bat's speed before and after collision.
Find bat's speed before and after collision.
Answers
Answered by
drwls
The change in momentum of the ball equals that of the bat.
Vbat1 - Vbat2 = (0.145/0.916)*(40 + 32)
= 11.40 m/s
The bat slows down after hitting the ball.
Now use conservation of energy to solve for the bat's initial velocity, Mbat1.
(1/2)Mbat*Vbat1^2 + (1/2)Mball*34^2
= (1/2)Mbat*(Vbat1-11.40)^2 + (1/2)
Mball*40^2
Vbat1 - Vbat2 = (0.145/0.916)*(40 + 32)
= 11.40 m/s
The bat slows down after hitting the ball.
Now use conservation of energy to solve for the bat's initial velocity, Mbat1.
(1/2)Mbat*Vbat1^2 + (1/2)Mball*34^2
= (1/2)Mbat*(Vbat1-11.40)^2 + (1/2)
Mball*40^2
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